Question

4. The size of the perimeter of the square ABCD is equal to 100 cm. The length of the segment
MN is equal to 5 cm and the triangle MNC is isosceles. Find the area of the pentagon ABN MD.

Answer 1

Answer:

Right scalene triangle.

Sides: a = 3.536   b = 3.536   c = 5

Area: T = 6.25

Perimeter: p = 12.071

Semiperimeter: s = 6.036

Angle ∠ A = α = 45° = 0.785 rad

Angle ∠ B = β = 45° = 0.785 rad

Angle ∠ C = γ = 90° = 1.571 rad

Area of the square - area of the triangle =100 - 6.25 =93.75 cm^2 - area of the pentagon ABNMD

The perimeter is the continuous line forming the boundary of a closed geometric figure