Math, asked by Anonymous, 7 months ago

4. The smallest natural number, which when added to the difference of
squares
of 17 and 13 gives a perfect square, is
(a) 5
(b) 4
(c) 21
(d) 1
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And correct answer is d) is correct but u have to solve it step by step. ​

Answers

Answered by mahi735
0

Step-by-step explanation:

(17)²-(13)²

289-169

120

when we add 1 in 120 we get 121 which is square of 11.

Answered by Anonymous
33

The difference of squares of 17 and 13 is given by 17

The difference of squares of 17 and 13 is given by 17 2

The difference of squares of 17 and 13 is given by 17 2 −13

The difference of squares of 17 and 13 is given by 17 2 −13 2

The difference of squares of 17 and 13 is given by 17 2 −13 2

The difference of squares of 17 and 13 is given by 17 2 −13 2 =289−169=120

The difference of squares of 17 and 13 is given by 17 2 −13 2 =289−169=120The nearest square number to 120 is 121 i.e 11

The difference of squares of 17 and 13 is given by 17 2 −13 2 =289−169=120The nearest square number to 120 is 121 i.e 11 2

The difference of squares of 17 and 13 is given by 17 2 −13 2 =289−169=120The nearest square number to 120 is 121 i.e 11 2 .

The difference of squares of 17 and 13 is given by 17 2 −13 2 =289−169=120The nearest square number to 120 is 121 i.e 11 2 .Hence, we need to add 1 to the given expression.

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