4. The smallest natural number, which when added to the difference of
squares
of 17 and 13 gives a perfect square, is
(a) 5
(b) 4
(c) 21
(d) 1
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And correct answer is d) is correct but u have to solve it step by step.
Answers
Step-by-step explanation:
(17)²-(13)²
289-169
120
when we add 1 in 120 we get 121 which is square of 11.
The difference of squares of 17 and 13 is given by 17
The difference of squares of 17 and 13 is given by 17 2
The difference of squares of 17 and 13 is given by 17 2 −13
The difference of squares of 17 and 13 is given by 17 2 −13 2
The difference of squares of 17 and 13 is given by 17 2 −13 2
The difference of squares of 17 and 13 is given by 17 2 −13 2 =289−169=120
The difference of squares of 17 and 13 is given by 17 2 −13 2 =289−169=120The nearest square number to 120 is 121 i.e 11
The difference of squares of 17 and 13 is given by 17 2 −13 2 =289−169=120The nearest square number to 120 is 121 i.e 11 2
The difference of squares of 17 and 13 is given by 17 2 −13 2 =289−169=120The nearest square number to 120 is 121 i.e 11 2 .
The difference of squares of 17 and 13 is given by 17 2 −13 2 =289−169=120The nearest square number to 120 is 121 i.e 11 2 .Hence, we need to add 1 to the given expression.