Question

4) The speed of an airplane is 1240 km per hour. Find the distance covered by the airplane in 3
hours and 20 min also express the distance in scientific notations.
​

Answer 1

Answer:

Distance = 4133.33 Kms

Step-by-step explanation:

Speed of aeroplane= 1240 Km per hour

Time taken = 3 hours 20 minutes

= 60 minutes *3 + 20 minutes

=200 minutes

Time taken by aeroplane in Hours = 200/60

Speed = Distance/ Time

Distance = Speed * Time

= 1240 * (200/60)

= 4133.33 Kms

Answer 2

$\sf\huge\bold{Answer:}$

Given :

• speed of an airplane = 1240 km/h
• Time=3hrs20min

To find :

Distance covered by plane

Solution :

$\fbox{Formula used :}$

$\tt\red{ :⟶distance = speed \times time}$

Speed=1240km/h

Time=3hr+20min

[1min=1/60hr]

=3hr+(20/60)hr

=3hr+⅓hr

=3⅓hr

• Inserting values in formula :

$\tt\ :⟶d = \big(1240\times 3 \frac{1}{3} \big)km$

• Converting mixed fraction into improper fraction

$\tt\ :⟶d = 1240 \times \frac{3 \times 3 + 1}{3} \: \: \: km$

$\tt\ :⟶d = \big(1240 \times \frac{10}{3} \big)km$

$\tt\ :⟶d = \big( \frac{12400}{3} \big)km$

$\tt\ :⟶d = 4133.33...km$

$\tt\ :⟶d ≈ 4133.3km$

Distance covered by plane is 4133.3km

• Converting distance in scientific notation

$\tt\ :⟶d = 4133.3 \times \frac{1000}{1000} \\ \:$

$\tt:⟶d=4.1333\times 10 {}^{3}$

$\tt:⟶d=4.13\times 10 {}^{3}$

$\tt\purple{d=4.13 \times 10 {}^{3} }$

Distance covered by plane is 4.13×10³ km