Question

4) The speed-time graph below shows the journey of a train between stations.
Find

a) the acceleration of the train at the start of the journey?
b) the deceleration of the train at the end of the journey?
c) the total distance traveled by the train in kilometers?

Round your answers to 1 decimal place where necessary.

Answer 1

Answer:

a) 2.7 m/s²

b) -2.3 m/s²

c) 9.8 km

Explanation:

a) Finding the acceleration of the train at the start of the journey.

=> (80-0) ÷ 30

=> 80 ÷ 30

=> 2.7 m/s²

b) Finding the deceleration of the train at the end of the journey.

=> (0-80) ÷ (155-120)

=> -80 ÷ 35

=> -2.3 m/s²

c) Finding the total distance travelled by the train in meters.

=> Area of Trapezium = Total distance travelled by the train

=> Area of Trapezium = [(b1+b2) h] ÷ 2

=> Area of Trapezium = [(155+90) 80] ÷ 2

=> Area of Trapezium = [(245) 80] ÷ 2

=> Area of Trapezium = 19600 ÷ 2

=> Area of Trapezium = 9800 m

   Finding the total distance travelled by the train in kilometers.

=> 1000 m = 1 km

=> 9800 ÷ 1000

=> 9.8 km

I hope it was helpful.