4. The students of two classes are to stand separately into rows having same nu
of students. There are 24 and 36 students in the two classes. How many maxi
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number of students will stand in each row?
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Answers
Answered by
0
Answer:
This is the answer
Step-by-step explanation:
Let the original number of rows =x
Let the original number of students in each row =y
Total number of students in class = Number of students × Number of rows =xy
According to problem
Case 1
Total no of students =(y+1)(x−2)=xy
⇒xy−2y+x−2=xy
⇒x−2y=2 ...(1)
Case 2
Total no of students =(y−1)(x+3)=xy
⇒xy+3y−x−3=xy
⇒x−3y=−3 ...(2)
Subtracting eq(1) from eq(2) we get
−y=−5
⇒y=5
Putting the value of y in eq(1)
x−2(5)=2
⇒x=12
Hence we get x=12 and y=5
Total no. of students =xy=60
Answered by
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Answer:
24+36=60 now two classes so,60/2=30.
THUS 30 STUDENTS IN EACH ROW.
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