Question

4. The sum of a two-digit number and the number
obtained by reversing its digits in 121. Find the
number, if its units place digit is greater than
the tens place digit by 7.
​

Answer 1

Step-by-step explanation:

digit number is y and the tens place digit is

X.

.. the number is 10x + y

.. the number obtained by reversing the

digits is 10y + x

:: from the given conditions,

(10x + y) + (10y + x) = 121

:: 11x+11y=121

..(1)

Also, x=y+7

.

.(I)

: Adding (1) and (II), 2x 18

:: from (1) a + y = 11 y= 2

: the two digit number is 29.

Answer 2

Step-by-step explanation:

I hope u understand what is it okay thank you