Question

4. The sum of digits of a two digit number is
10. The number obtained by interchanging the
digits is 36 more than the original number.
Find the original number.

Answer 1

Answer:37

Step-by-step explanation:

Let the digit at ones place=x

Therefore the digit at tens place=10-x

Ten digit no.=10×tens digit + ones digit

=10×(10-x)+x

=100-10x+x=100-9x

No. obtained by interchanging the digits=

Ten digit no.=10×tens digit + ones digit

=10×x+(10-x)

=10x+10-x= 9x+10

ACQ

100-9x+36=9x+10

136-9x=9x+10

-9x-9x=10-136

-18x=-126

x=-126/-18

x=7

Ones digit=7

Tens digit=10-7=3

Original no.=37