Question

4. The sum of the digits of a two-digit number is 14. The number is nineteen times the digit at its
one's place. Find the number.​

Answer 1

Answer =95

step- by - step - explanation

number = 10 (x) + y10x + y = 19 y10x - 18y

= 010x - 18 (14 - x )

= 010× - 252 + 18 x

= 028x - 252x

= 9y = 14 - xy

= 5Number = 10(9)+5

=95

hope it's helpfull

Answer 2

Answer:

95

Step-by-step explanation:

⇒Let the first digit number be $x$ and the second digit be $f$

⇒So $xf$ is the number, we can write this number in powers of 10

⇒$xf$ =(10 ^1)$x$ + (10^0)b$f$

⇒This number is 19 times the first digit:

⇒19(( 10^0)$f$) = (10^1)$x$ + ((10^0)$f$)

⇒solve for first digit $x$:

⇒19$f$ = 10$x$ + $f$

⇒18$f$ = 10$x$

⇒$x$ = 1.8$f$

⇒substitute $x$ in the following equation and solve for $f$

⇒$x$ + $f$ = 14

⇒(10^1 * $x$) + (10^0 *$f$) = 14

⇒1.8$f$ + $f$ = 14

⇒2.8$f$ = 14

⇒$f$ = 5

⇒substitute $f$ in the following equation and solve for $x$:

⇒19$f$ = 10$x$ + $f$

⇒18 * 5 = 10$x$

⇒$x$ =9

⇒The number is $xf$, $x$ =9,  $f$ = 5 so the number is 95.

⇒verification:

⇒9 + 5 =14

⇒95/5 = 19