Question

4. The sum of the first 7 multiples of 8 is:
(b) 40
(a) 30
(c) 89
(d) 224
​

Answer 1

here is your answer

Step-by-step explanation:

the sum of the first 7 multiple of 8 is

d) 224

Answer 2

☆ ANSWER:-

${\large{\tt{\blue{\bold{Option\:D\::-\:224.}}}}}$

$\rule{200}2$

☆ Explanation:-

▪︎ Given:-

• First 7 multiples of 8.

▪︎ To Find:-

• The sum of first 7 multiples of 8.

▪︎ Formula Used:-

$\tt\mapsto \: s \frac{}{n} = \frac{n}{2} (a + a \frac{}{n})$

Where,

• n = Number of terms.

• Sn = Sum of n terms.

• a = First term.

• an = nth term.

▪︎ Now,

We have to find the sum of first 7 multiples of 8, which are:-

$\tt\mapsto 8,\: 16,\:....56$

▪︎Clearly,

We can see that the above terms are in AP with common difference 8 and with nth term 56, because 8×7 = 56.

▪︎ So,

$\leadsto$ Sum of first7 multiples of 8:-

$\tt = \frac{7}{2}(8 + 56) \\ \\ \tt = \frac{7}{\cancel{2}}( \cancel 64) \\ \\ \: \tt = 7 \times 32 \\ \\ \tt \huge\fbox\red{ = 224.}$

Therefore The Sum Of First 7 Multiples Of 8 is 224.

$\small\tt\fbox\pink{So\:The\:Final\:Answer\:Is\:Option\:D}$

$\rule{200}4$

☆ More Formulas Of AP:-

=》 Sn=n/2 {2a+(n-1)d}.

=》 an = a + (n-1)d.

=》 d = a2 - a1.

• Where d is common difference.

• a2 = Second Term.

• a1 = First Term.