Question

4. The sum of three consecutive integers is 11 more than the smallest integer. Find the integers​

Answer 1

I am not sure but it can be

Answer 2

Aɴsᴡᴇʀ :-

Let the first integer be x.

Then, second integer = x + 1 and third integer = x + 2.

Sum of the integers = x + 11

ATQ,

➡️ x + x + 1 + x + 2 = x + 11

➡️ 3x + 3 = x + 11

➡️ 3x - x = 11 - 3

➡️ 2x = 8

➡️ x = 4

Hence, first integer = 4

second integer = (4 + 1) = 5

third integer = (4 + 2) = 6