Question

4. The sum of three consecutive multiples of 5 is 345. Find the multiples.

Answer 1

let the multiples be 5x, 5x+5, 5x+10.

ATP,

5x+5x+5+5x+10= 345

=>15x+15=345

=> 15(x+1)=345

=> x+1= 345/15

=> x+1= 23

=> x= 22

Therefore,the multiples are 110,115,120...

Hope it helps you dear... PLEASE MARK ME AS A BRAINLIEST!!

Answer 2

Let the consecutive numbers be 5x , 5x+5, 5x+10.

Now,ATQ-
5x+5x+5+5x+10= 345
15x+15=345
15x=345-15
15x=330
x=330/15
x=22


As per question,
5x=5*22=110
5x+5=110+5=115
5x+10=110+10=120

Hence the consecutive multiples are 110,115 and 120.
Hope it helps..♥️♥️....mate!!!!