4. The sum of three consecutive multiples of 7 is 63. Find these multiples.
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Let three consecutive multiples of 7 be 7x,7x+7 and 7x+14
Sum of three consecutive multiples of 7 = 63
7x+7x+7+7x+14 = 63
21x+21 = 63
21(x+1) = 63
(x+1) = 63/21
x+1 = 3
x = 2
therefore,
The multiples are 7(2) = 14
7x+7 = 14+7 = 21
7x+14 = 14+14 = 28
Sum of three consecutive multiples of 7 = 63
7x+7x+7+7x+14 = 63
21x+21 = 63
21(x+1) = 63
(x+1) = 63/21
x+1 = 3
x = 2
therefore,
The multiples are 7(2) = 14
7x+7 = 14+7 = 21
7x+14 = 14+14 = 28
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