4. The sum of two consecutive multiples of 5 is 65. Find the numbers.
5. Thrice a number, when increased by 7 gives 40. Find the number.
Answers
4. 5x + 5x+5= 65
10x= 60
x= 6
the numbers are---
5(6) = 30
5(6)+5 = 35
5. 3x+7= 40
3x= 33
x= 11
the number is 11
☆ Question ☆
The sum of two consecutive multiples of 5 is 65. Find the numbers.
☆ To find ☆
The numbers.
☆ Solution ☆
Let the number be x.
Since the numbers are consecutive, the other number = (x+1).
According to condition,
5x + 5(x+1) = 65
→ 5x + 5x + 5 = 65
→ 10x + 5 = 65
→ 10x = 65 - 5
→ 10x = 60
→ x = 60/10
→ x = 6
☆ Hence ☆
☞ One number = x = 6
☞ Other number = (x+1) = (6+1) = 7
☆ Therefore ☆
The two numbers are 6 and 7 respectively.
☆ Question ☆
Thrice a number, when increased by 7 gives 40. Find the number.
☆ To find ☆
The number.
☆ Solution ☆
Let the number be x.
According to condition,
3x + 7 = 40
→ 3x = 40 - 7
→ 3x = 33
→ x = 33/3
→ x = 11
☆ Hence ☆
☞ The number = x = 11
☆ Therefore ☆
The required number is 11.
๑ Hope this helps you. ๑