Question

4. The surface area of an object is 20 m² and a force of 10 N is applied on it, then what
is the pressure? (AS,)​

Answer 1

Given :-

• Surface area (A) = 20m²
• Force (F) = 10N

To Find :-

• What is the Pressure (P).

Solution :-

As we know that,

${ \boxed{ \rm{ \red{</u><u>\</u><u>underline{</u><u>P = \frac{F}{A} }}</u><u>}</u><u>}}$

[ Putting values ]

▶ P = 10/20

▶ P = 0.5 N/m²

[ °.° N/m² = Pascal ]

▶${\boxed{\blue{\rm{\underline{P = 0.5pa.}}}}}$

Hence,

• The required pressure is 0.5pa.

Answer 2

$\sf\large\underline\green{Given:-}$

$\sf{\implies Surface\: area\:_{(of\:object)}=20m^2}$

$\sf{\implies Force\:applied\:_{(on\:object)}=10N}$

$\sf\large\underline\green{To\: Find:-}$

$\sf{\implies Pressure\:_{(on\:object)}=?}$

$\sf\large\underline\green{Solution:-}$

• To calculate pressure on object here , we have to use a formula by applying the formula of pressure we can calculate the pressure with the help of given clue in the question . As you know P=F/A :-]

$\sf\large\underline\red{Formula\:Used:}$

$\tt{\implies Pressure=\dfrac{Force}{Area}}$

$\sf\large\underline{Here,\:\:Area=20m^2\:\: Force=10N:}$

$\tt{\implies Pressure=\dfrac{10}{20}}$

$\tt{\implies Pressure=0.5\:N/m^2}$

$\tt{\implies Pressure=0.5\:pa\:or\: Pascal}$

$\sf\large{Hence,}$

$\sf{\implies Pressure\:applied\:_{(on\:object)}=0.5N/m^2\:or\: Pascal}$

$\sf\large\underline\purple{Some\: additional\: information:-}$

Pressure:- The force which is applied on the surface of the object is called pressure.

It's unit is measured in Newtown per metre square.

Force:- A force is a pull or push on the surface of objects. When applied force on any object then the object move.

Area:- A portion of area where pressure or force is applied.