Question

4) The taxi charges in a city consist of a fixed charge together with the charge for
distance covered for a distance of 10 km, the charge pad is 105 and for
Joumey of 15 km. the charge paid ise 155. What are the fixed charges and me
charge per km? How much does a person have to pay for travelling a distance
25 lom?
9
(5) A fraction becomes
if 2 is added to both the numerator and the denominate
11
II, 3 is added to both the numerator and the denominator it becomes
Find the
fraction
(6) Five years hence, the age of Jacob will be three times that of his son. Five years
ago, Jacob's age was seven times that of his son. What are their present ages?
$plz \: answer \: fast$
​

Answer 1

Answer:

Hello mate ✌️

Step-by-step explanation:

Let x be the fixed charge and y be the additional charge per km,

Thus, the charge for 10 km,

x + 10 y,

And, the charge for 15 km,

x + 15 y

According to the question,

x + 10 y = 105 -------(1)

x + 15 y = 155 --------(2),

Equation (2) - Equation (1),

5 y = 50

⇒ y = 10,

From Equation (1),

We get, x = 5

Hence, the charges for 25 km = x + 25 y = 5 + 25 × 10 = 5 + 250 = 255 rupees.

hope it will be helpful to you ✌️✌️

mark as brainlist answer ❣️❣️❣️

follow up me ✔️ for inbox ✌️ guys