Question

4. The taxi fare in a city is as follows: For the first kilometre, the fare is 38 and for the
subsequent distance it is 5 per km. Taking the distance covered as x km and total
fare asy, write a linear equation for this information, and draw its graph.​

Answer 1

Answer:

5x + 33 - y = 0

Step-by-step explanation:

y = 5(x-1) + 38

y = 5x - 5 + 38

y = 5x + 33

5x + 33 - y = 0

Answer 2

Answer:

Hey mate,

Your answer is as follows:

Given,Total distance covered= x km=1+(x-1)km

Fare For first kilometre= ₹8

Fare for subsequent distance= ₹5 per km

Fare for next(x-1)km= 5(x-1)

A.T.Q

Total fare= y

8+5(x-1)=y

8+5x-5=y

5x-y+3=0

Which is the required linear equation.

It can also be written as y= 5x+3

When X = 0 ,then Y = 3,When x=1, then y= 5+3=8

When x= 2, then y= 10+3=13

 [Table & graph are on the attachment]

Now plot the points A(0,3), B(1,8), C( 2,13) on the graph paper and join them to form a line BC, which represents the required graph of linear equation.

Explanation:

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