.4 The top of a palm tree forms an angle of 300 with a point 3 m away from its base. How tall is the tree?
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Let C be the point at which the tree is broken and let the top of the tree touch the ground at A.
Let B denote the foot of the tree.
Given AB=30m and ∠CAB=30∘
In the right angled △CAB,
tan30∘=ABBC
⇒BC=ABtan30∘
∴BC=330
=103m (1)
Now, cos30∘=ACAB
⇒AC=cos30∘AB
So,
AC=330×2=103×2=203
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