Math, asked by hervindersinghp9zhps, 3 months ago

4. The value of k for which the system of equations x +
y - 4 = 0 and 2x + ky = 3, has no solution, is
(a) - 2
b) #2​

Answers

Answered by kavitakuldeep225
2

Answer:

a)-2 is right answer

Step-by-step explanation:

mark as brainlest


nayan00790: hello
Answered by Anonymous
5

Answer:

  • K = 2

Given:

  • x +y - 4 = 0

  • 2x + ky = 3

Solution:

  • x + y - 4 = 0
  • 2x + ky = 3
  • So 2x + ky = 3 becomes 2x+ ky - 3 = 0

As we know that:

For no solution

  • a1/a2 = b1/b2 ≠ c1/c2

Then,

● x / 2x = y / ky

● 2xy = kxy

● k = 2

Hence no solution is k = 2

Explanation more:

  • No solution means there is no number that can substituted to the make the equation true
  • Example : x + 8 = x+3 = 8 ≠ 8 so, 8 is not equal to 3 then its no solution

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