Question

4.The value of (x - y)(x + y) + (y - z)(y + 2) + (z - x) (z + x) is*​

Answer 1

Answer:

$(x - y)(x + y) + (y - z)(y + z) + (z - x)(z + x) = 0.$

Step-by-step explanation:

$(x - y)(x + y) + (y - z)(y + z) + (z - x)(z + x) = {x}^{2} - {y}^{2} + {y}^{2} - {z}^{2} + {z}^{2} - {x}^{2} \\ \\ = 0.$