Question

4. The vertical component of acceleration at
60° with the vertical is 5 m/s2. Find the mag-
nitude of acceleration and its horizontal
component is m/s2
(A) 10,572
(B)15,573
(C)10,573
(D) 15,572​

Answer 1

Answer:

Vertical is square root of 5 m/s, horizontal is double of that.

Explanation:

Simple application of Pitagora’s theorem c^2=a^2+b^2. But because angle is 60 you know that b=2a, so c^2=5*a^2. Thus a^2=c^2/5, and then a is equal to c divided by square root of 5, which is equal to c times square root of five and then all that divided by 5. Because c is 5, and 5/5=1, a is equal to square root of 5m/s. Then b=2a can be solved