Question

4. The volume of a cylinder is 2512 cu cm and its height is 12.5 cm. Find the radius of the base.
$(\pi = 3.14)$
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Answer 1

Step-by-step explanation:

$\pi \: r {}^{2} = 2512 \div 12.5 \\ = 200.96 \\ {r }^{2} = 200.96 \div 3.14 \\ = 64 \: (r = \sqrt{64 \: = 8})$

Answer 2

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GIVEN THAT:

$➾$ The volume of cylinder = 2512 cm3

$➾$ Height of cylinde (h) = 12.5 cm

FORMULA;

$➾$ The volume of cylinder(V) = πr2h

where,

• r = radius of the bace of cylinder

• h = Height of cylinder

SOLUTIONS;

$➾$ The volume of cylinder

$&#10230 \: \: \pi {r}^{2} h = 2512 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ &#10230 \: \: 3.14 \times {r}^{2} \times 12.5 = 2512 \\ &#10230 \: \: 39.25 \times {r}^{2} = 2512 \: \: \: \: \: \: \: \: \: \: \: \\ &#10230 \: \: {r}^{2} = \cancel\frac{2512}{39.25} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ &#10230 \: \: {r}^{2} = 64 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ &#10230 \: \: r = \sqrt{64} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ &#10230 \: \: r = 8cm \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$➾$ So the radius of base of cylinder = 8 cm