Question

4
There are two buildings standing on the opposite sides of a park. A ladder, 17 m long
reaches a point on a building at a height of 15 m from the ground. The ladder is now turned
to the other building on the other side of the park keeping its foot at the same point. The
ladder now reaches a point on this building at a height of 8 m above the ground. Find the
distance between the two buildings.​

Answer 1

Answer:

the distance between the two buildings are 23m

Step-by-step explanation:

in building A:

length of PQ (ladder)= 17 m

length of PS( height of building where the ladder reached) = 15 cm

so, SQ² = (PQ)² - (PS)²

》 SQ²= 17² - 15²

》 SQ²= 289 - 225

》 SQ = 64^½

》 SQ = 8

So, SQ = 8m

in building B:

length of QR = 17m

length of RT = 8m

so, QT² = QR²- RT²

》 QT²= 17² - 8²

》 QT²= 289- 64

》 QT = 15

So, QT= 15m

now, total distance between the two buildings = SQ+QT

= (8+15) m

= 23m