Question

4. There is a pentagonal park. Neha and Nidhi divided it in two different ways to
find its area.
28 m
15 m
12 m
Neha's figure
Nadh s figure
Fig. 14.13
Find the area of the park in both ways.​

Answer 1

Answer:

Consider the given pentagonal park.

Let us find the area of the park which Neha divided.

Neha divided the pentagonal park into two trapezoids.

So, area of the park = 2 \times Area of trapezoid

= 2 \times \frac{(a+b) h}{2}

where 'a' and 'b' are the lengths of the parallel sides of the trapezoid and 'h' is the height

= 2 \times \frac{(15+28) \times 6}{2}

= 258 square meters.

Now, let us find the area of the park which Nidhi divided. Nidhi divided the park into one triangle and one rectangle.

So, area of the park = area of triangle + area of rectangle

= \frac{1}{2} bh + lw

where 'b' is base and 'h' is height of the triangle and 'l' is length and 'w' is width of the rectangle.

=(\frac{1}{2} \times 12 \times 13) + (15 \times 12)

= 78 + 180

= 258 square meters.

Answer 2

Answer:

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