Math, asked by divyanshbabbar669, 7 months ago

4. There is a square park of dimension 35 m. There are 2 semi circular
cemented flower beds on two opposite sides of the park as shown in the
figure. Find the area and perimeter of the square park including the flower
beds.​

Answers

Answered by deepikamr06
4

Answer:

Area of the park including the flower beds=2*22/7*35/2*35/2*1/2+35*35=962.5+1225=2187.5cm^2...now..perimeter of the figure=35+35+2*22/7*35/2=180cm

Answered by aditya1154
4

Answer:

area \: of \: square =  {35}^{2}  = 1225 {m}^{2}  \\ area \: of \: semi \: circle = 2( \frac{\pi {r}^{2} }{2} ) =  \frac{22}{7}  \times  \frac{35}{2}  = 11 \times 5 = 55 {m}^{2}  \\ area \: of \: the \: park \: including \: the \: flower = 1225 + 55 = 1275 {m}^{2}

perimeter \: of\: square = 4 \times 35 = 180m \\ perimeter \: of \: semi \: circle =\frac{2\pi \: r}{2}  =  \frac{2 \times 22 \times 35}{2 \times 2 \times 7}  = 55m \\ total \: perimeter = 180 + 55 = 235m

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