Question

4. Three angles of a quadrilateral are in the ratio
2:6: 4. The difference of the least and the
greatest of angles out of these angles is the fourth
angle. Find all the angles of the quadrilateral.​

Answer 1

Step-by-step explanation:

let take the unknown ratio ne x

2x+6x+4x+x =360°

12x+x=360°

transporting 12 to RHS side

x+x=360/12=30

2x=30

x=30/2=15°

then x=15°

the largest side is 6X15=90°

and the least number is x which is 15°

difference between those is 90-15=75

HOPE IT'S HELPFUL