Question

4) Three resistors of resistances 20Ω, 40Ω and 60Ω are connected in parallel.

Find the equivalent resistance of the combination.

a) 20Ω (b) 33.4Ω (c) 10.91Ω (d) 2.17Ω​

Answer 1

Answer:

10.91 ohm

Explanation:

The three resistors are connected parallelly;

Therefore, the equivalent resistance is: 1/Re = 1/R1 + 1/R2 + 1/R3

Substituting these values,

1/Re = 1/20 + 1/40 + 1/60

1/Re = (6+3+2)/120 [LCM of 20,40,60 is 120]

1/Re = 11/120

Re = 120/11

Re = 10.91 ohm

Answer 2

Here,

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.

.

‡ Those resistors are connected in parallel.

So, Equivalent resistance (R) →

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.

$\implies \large \color{orange}{\bold{ R ≈ 10.91 Ω }}$