Question

4. Three wires of lengths 48 m, 80 m and 96 m are to be cut into equal pieces. Find the greatest
length of the pieces that can be cut.​

Answer 1

to find the greatest length find the hcf of the numbers ...

the HCF of 48,80 and 96 is

16..

so 16 will be the answer ..

Hope this helps u dear☺☺

Answer 2

Answer:

HCF of  48 m, 80 m and 96 m gives us the required length to be cut..

So factors of 48 = 1,2,3,4,6,8,12,16,24,48

factors of 80 = 1,2,4,5,8,10,16,20,40,80

factors of 96 = 1,2,3,4,6,8,12,16,24,32,48,96

CF = 1,2,4,8,16

HCF = 16

So it has to be cut into 16 m