Question

4. Through a rectangular field of length 90m and breadth 60m, two roads are constructed
which are parallel to the sides and cut each other at right angles through the centre of the
fields. If the width of each road is 3m. Find
(i) The area covered by the roads.
(ii) The cost of constructing the roads at the rate of Rs.110 per m 2
•

Answer 1

Solution:

This is a problem of area and length from mathematics.

In this case,

Area of road parallel to length $=90 \mathrm {m} \times 3 \mathrm{m}=270 \mathrm {sq} \mathrm{m}$

Area of road parallel to breadth$=60 m \times 3 m=180 \mathrm {sq}$

But,

Four plots of length and breadth 3 m is counted

twice.

So, total area will be =270 $\mathrm {sq} \mathrm{m}+180 \mathrm {sq} \mathrm{m}-3 \times 3 \mathrm {sq} \mathrm$

$=270 \mathrm {sq} m+180 \mathrm {sq} \mathrm{m}-9 \mathrm {sq} \mathrm{m}$

$=441 \mathrm {sq} \mathrm{m}$

So, the area of pavement required to fill up the area of the road is

441 sq m.

Answer 2

Answer:

1. area covered by road = 90×3 + 60×3 - 3×3

=441m square

2. cost of construction= 110× 441

= RS 48510