Physics, asked by khushiaggarwal172, 8 months ago

4. Time period of simple pendulum is measured to be
T = (2.5 +- 0.1) s, then percentage error in
measurement is

(1) 2%
(2) 4%
(3) 1%
(4) 2.5%​

Answers

Answered by umarmemon93
22

Answer:

Explanation:

%error=mean absolute error/mean×100

0.1/2.5×100 =1/25×100=4%

Answered by ShreyaNegi02
13

Answer:  

Percentage error in time period of simple pendulum T = (2.5 +- 0.1) is 4%

.So correct option is (2)

Explanation:

Ratio of mean absolute error to the mean value of quantity measured in per centage form is called percentage error

  If   A= (a +- Δa)  

then percentage error

= (Δa/a ) ×100

Given :  T= (2.5 +- 0.1)

so ,

δt  =  \frac{0.1}{2,5} *100    

      (δ represents percentage error)

δt = 4%

hence percentage error is 4%

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