Question

4 times 5 less than the sum of 13 and 7 is divided by the difference of 11 and 6​

Answer 1

4×5-(13+7)÷(11-6)

20-20÷5

20-4

16

we did brackets first, then divison and then addition a d then subtraction.

following the rules of "BODMAS"

Answer 2

Concept:

Basic arithmetic operations are used such as Division, multiplication, Addition, and subtraction.

Given:

4 times 5 less than the sum of 13 and 7 is divided by the difference of 11 and 6​.

Find:

We are asked to find out the value of the given statement.

Solution:

We have

4 times 5 less than the sum of 13 and 7 is divided by the difference of 11 and 6​,

Now,

4 times 5 = 4 × 5 ,

And,

sum of 13 and 7 = (13 + 7),

And,

Difference of 11 and 6 = (11 - 6)

So,

Now,

According to the question,

= [(13 + 7) - (4 × 5)] / [(11 - 6)]

= [ 20 - 20] / 5

= 0/5

= 0

Hence, the value of the given statement is 0.

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