Question

4 tube lights of 40 W each and 2 fans of 100 W each are
mains and operate on an average of 8 h a day. If energy costs Rs. 2 per kWh
calculate
i) monthly bill
ii) minimum fuse rating.
.
​

Answer 1

The probable answer might be —

Energy used by light bulbs in one day= 40w*5*4= 0.8 kwh

Energy used by tube lights in one day= 60w*5*4=1.2 kwh

Energy used by TV in one day= 100w*6= 0.6 kwh

Energy used by washing machine in one day= 400w*3= 1.2 kwh

So, total energy used in one day= 0.8+0.6+1.2+1.2= 3.8 kwh

Total energy used in 30 days (April has 30 days) = 3.8*30= 114 kwh

Now, 1 kwh= 1 unit

And, Cost per unit= Rs. 1.8

Therefore, the bill for the entire month = 114*1.8= Rs. 205.2

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