4. Two boxes containing candies are placed on a table. The boxes are labelled B1 and B2. Box B1 contains 7 cinnamon candies and 4 ginger candies. Box B2 contains 3 cinnamon candies and 10 pepper candies. The boxes are arranged so that the probability of selecting box B1 is 1⁄3 and the probability of selecting box B2 is 2⁄3. Suresh is blindfolded and asked to select a candy. He will win a colour TV if he selects a cinnamon candy. If he wins a colour TV, what is the probability that the cinnamon candy was from the first box
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Answered by
28
dont know the answer. .....sorry. ...
Answered by
26
Answer:
91/157
Step-by-step explanation:
probability of getting cinamon candy from box1
= (1/3)(7/11) = 7/33
from box 2 = (2/3)(3/13) = 2/13
total probability of getting cinamon candy
= 7/33 + 2/13
= (91+66)/(429)
= 157/429
probability from getting box1
= (7/33)/(157/429)
= (7 *429)/( 33 *157)
= (7 * 13)/ 157
= 91/157
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