Question

4. Two forces, 437 N at 18° and 317 N at 35° are applied to a car in an effort to accelerate it.






a. What is the magnitude of the resultant of these two forces?
b. What is the direction of the resultant force?
c Assuming there is no friction and the car has a mass of 3800 kg, what acceleration does it have?

cbef90f940785d74c93a91846e34210b.docx

Answer 1

$\huge\mathfrak{\bf{\underline{\underline{\blue{Answer \ :}}}}}$

Let , magnitude of the two forces be F1 and F2.

Given,

for gr ether resultant θ=0 = F12+F22+2F1F

2

cos0

=

(F

1

+F

2

)

2

=F

1

+F

2

=7N............(i)

Now,forleastresultantθ=180

0

=

F

1

2

+F

2

2

+2F

1

F

2

cos

180

=

(F

1

+F

2

)

2

A

=F

1

+F

2

=3N............(ii)

Adding equation (i) and (ii) we get,

2F

1

=10;F

1

=5N

Putting value of F

1

in (i) we get,

F+2=2N

After adding 3N to each force we get,

F

1

′

=8N

F

2

′

=5N

When they are applied at θ=60

0

Resultant force F will be,

After solving we will get,

F=

129

N