Question

4.
Two identical pendulums A and B are suspended
from the one point. The bobs A and B are given
positive charges Q. and Q, respectively. If mass of
A and B are m, and m, (m, > m.) and angles
from vertical of A and B are e, and e, respectively
(1) theta1 = theta2
(2) theta1 >theta2
(3) theta1<theta2
(4) theta1>and= theta2
​

Answer 1

If two identical pendulums are suspended at the same point then theta1 = theta2.

• The electrostatic force between two charges is directly proportional to the product of the magnitude of charges and inversely proportional to the distance square between them, according to Coulomb's law.
• Therefore, both the pendulums will experience an equal force and they will possess the same tension.
• Hence, it can be concluded that they will make equal angles with the vertical.

Answer 2

Given that,

Two identical pendulums A and B are suspended  from the one point.

The bobs A and B are given  positive charges Q. and Q, respectively.

The mass of  A and B are m and m, if mass of A is greater then mass of B.

If the angles  from vertical of A and B are θ₁, and θ₂, respectively

We need to calculate the force acting on both the particles

Using formula of force

$F=\dfrac{kQq}{r^2}$

Here, Q = q

Put the value into the formula

$F=\dfrac{kq^2}{r^2}$

The force acting between them is the same and thus they will make the same angle from the vertical.

Hence, The angle from vertical of A and B will be θ₁ =θ₂.

(1) is correct option.