Question

4. Two nurnber are in the ratio of 15 : 11. IF
their HCF is 13. Then numbers will be:
(A) 195 and 143 (B) 190 and 140
(C) 185 and 163 (D) 185 and 193​

Answer 1

Answer:

A . 195 and 143

Step-by-step explanation:

First process :

Solution

The correct option is A

195 and 143

Let the required numbers be 15x and 11x.

Now, 15x = 15

×

x ...(i)

And, 11x = 11

×

x ...(ii)

From (i) and (ii), we can say that x is the highest common factor for both 15x and 11x.

∴

x is the H.C.F. of 15x and 11x.

It is given that the H.C.F of the numbers is 13.

∴

x

=

13

∴

The numbers are

15

×

13

and

11

×

13

i.e., 195 and 143.

second process :

From given,

let the numbers be,

15x,11x

since given,

HCF=13

we have,

15×13=195

11×13=143

195,143 are the numbers

Answer 2

Answer:

YOUR ANSWER:-

B) 190 AND 140