Math, asked by thomasyesudas, 5 months ago

4. Two parallel roads, Elm Street and Oak Street, are crossed by a third, Walnut Street, as shown in the figure. Find the measure of the acute angle formed by the intersection of Walnut Street and Elm Street.

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Answered by kaushalsahil
7

Answer:

Step-by-step explanation:

since elm parallel to oak , by alternate interior angle-

2x+33 =5x-15

x=16

thus 2x+33 =65

Answered by Anonymous
7

\huge\bold{{\pink{Q}}{\blue{U}}{\green{E}}{\red{S}}{\purple{T}}{\orange{I}}{\pink{O}}{\blue{N}}{\green{❥}}}

Two parallel roads, Elm Street and Oak Street, are crossed by a third, Walnut Street, as shown in the figure. Find the measure of the acute angle formed by the intersection of Walnut Street and Elm Street.

\huge\bold{{\pink{G}}{\blue{I}}{\green{V}}{\red{E}}{\purple{N}}{\green{❥}}}

  • Two parallel roads, Elm Street and Oak Street, are crossed by a third, Walnut Street.

\huge\bold{{\pink{T}}{\blue{O}}{\green{  }}{\red{F}}{\purple{I}}{\orange{N}}{\pink{D}}{\green{❥}}}

  • The measure of the acute angle formed by the intersection of Walnut Street and Elm Street.

\huge\bold{{\pink{S}}{\blue{O}}{\green{L}}{\red{U}}{\purple{T}}{\orange{I}}{\pink{O}}{\blue{N}}{\green{❥}}}

In the attached image,

  • \blue{\boxed{\pink{CD|| EF}}}

  • \pink{\boxed{\blue{AB\:is\:the\: transversal.}}}

  • \green{\boxed{\orange{AB\:cuts\:CD\:at\:O.}}}

  • \purple{\boxed{\red{AB\:cuts\:EF\:at\:P.}}}

So, ∠AOP and ∠EPO are opposite interior angles.

We know that if two lines are parallel, the opposite interior angles, formed by the intersection of the lines by a transversal, are equal.

So,

(2x+33)=(5x-15)

➳\:2x-5x=(-15)-33

➳\:-3x=-48

➳\:x={\frac{-48}{-3}}

➳\:x=16

\huge\bold{{\pink{H}}{\blue{E}}{\green{N}}{\red{C}}{\purple{E}}{\green{❥}}}

x=16

2x+33=(2×16)+33=32+33=65

5x-15=(5×16)-15=80-15=65

\huge\bold{{\pink{T}}{\blue{H}}{\green{E}}{\red{R}}{\purple{E}}{\orange{F}}{\pink{O}}{\blue{R}}{\red{E}}{\green{❥}}}

The measure of the acute angle formed by the intersection of Walnut Street and Elm Street is 65°.

\huge\bold{{\pink{D}}{\blue{O}}{\green{N}}{\red{E}}{\purple{࿐}}}

\bold\green{\boxed{{\blue{✿}}{\pink{H}}{\blue{O}}{\green{P}}{\red{E}}{\purple{  }}{\orange{T}}{\pink{H}}{\blue{I}}{\green{S}}{\red{  }}{\purple{H}}{\orange{E}}{\pink{L}}{\blue{P}}{\green{S}}{\red{  }}{\purple{Y}}{\orange{O}}{\pink{U}}{\blue{✿}}}}

\bold\red{\boxed{{\blue{✿}}{\pink{H}}{\blue{A}}{\green{V}}{\red{E}}{\purple{  }}{\orange{A}}{\pink{  }}{\blue{N}}{\green{I}}{\red{C}}{\purple{E}}{\purple{  }}{\orange{D}}{\pink{A}}{\green{Y}}{\blue{✿}}}}

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