Question

4. Two similar poles one is twice as strong as other repel with a force of 4 mN when separated by a distance of 10 cm. Then the pole strengths of two poles are​

Answer 1

Answer:

m1=m

m2=4m

y=10cm.=0.1m

F=64 gf

F=h°m1m2/4πr2

4m2=64

m=4 A-M

16=a-m

Answer 2

Answer:

The correct answer to this question

m₁ = 28.2 Am and m₂ = 14.14 Am

Explanation:

Coulomb's Law of magnetism:

• The force of attraction between the two magnetic poles which are at rest is directly proportional to the product of their pole strengths
• Formula: F = (μ₀/4π) * (m₁m₂ / r²)
• μ₀ - permeability
• m1,m2 are pole strengths
• r is the distance between poles

Note:

• μ₀/4π = 10⁻⁷

Given,

Force F = 4 mN = 4 × 10⁻³ N

m₁ = 2 m₂

r = 10 cm  = 0.1 m

using the above formula,

F = (μ₀/4π) × (m₁m₂ / r²)

4 × 10⁻³ = 10⁻⁷ × ((2m₂ * m₂) / (0.1)²)

4 × 10⁻³ = 10⁻⁷ × (2 m₂²) / 10⁻²

4 × 10⁻³ = 10⁻⁵ × (2 m₂²)

4 × 10⁻³ × 10⁵ = 2 m₂²

4 × 10² = 2 m₂²

2 m₂² = 400

m₂² = 200

m₂ = √200

m₂ = 14.14 Am

m₁ = 2 m₂

    = 2 × 14.14

    = 28.28

m₁ = 28.28 Am

Hence, the pole strengths of the two poles are

m₁ = 28.2 Am and m₂ = 14.14 Am

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