Question

4. Two supplementary angles are in the ratio 3:2. Find the angles.
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Answer 1

Step-by-step explanation:

Given:-

Two supplementary angles are in the ratio 3:2.

To find:-

Find the angles

Solution :-

Method -1:-

Two supplementary angles are in the ratio 3:2.

The ratio of the given angles = 3:2

Let they be 3x° and 2x°

Since they are Supplementary angles

Their sum should be equal to 180°

=>3x° + 2x° = 180°

=>5x° = 180°

=>x° = 180°/5

=>x° = 36°

The value of x= 36°

now,

3x° = 3×36° = 108°

2x°=2×36° = 72°

The angles are 108° and 72°

Method -2:-

Two supplementary angles are in the ratio 3:2.

The ratio of the given angles = 3:2

Total parts = 3+2=5

Since they are Supplementary angles

Their sum should be equal to 180°

=>5 parts = 180°

=>1 part = 180°/5

=>1 part = 36°

=>3 parts = 3×36°=108°

=>2 parts = 2×36° = 72°

The angles are 108° and 72°

Answer:-

The required two angles are 108° and 72°

Check:-

Their sum = 108°+72° = 180°

Their ratio= 108:72

=>108:72

=>108/72

=>(3×36)/(2×36)

=>3/2

=>3:2

Verified the given relations

Answer 2

$\Large{\underline{\sf{Given:}}}$

☞ Two Supplement Angles are in the ratio 3:2

$\Large{\underline{\sf{To\;Find:}}}$

☞ Values of the angles

$\huge{\underline{\underline{\bf{Solution:}}}}$

Let's

Angle A be '3x'

Angle B be '2x'

$→\;{\tt{3x+2x = 180°}}$

$→\;{\tt{5x = 180°}}$

$→\;{\tt{x = \frac{180°}{5}}}$

$➝\;{\bf{x = 36°}}$

Value of Angle A = 3x → 3×36° ➝ 108°

Value of Angle B = 4x → 2×36° ➝ 72°

$\Large{\green{\underline{\underline{\mathfrak{AnSweR:}}}}}$

Value of Angles ◕➜ $\Large{\red{\mathfrak{108°, 72°}}}$

Hope It Helps You ✌️