Question

4.
Two years ago, Bunty was three times as old as
his son and two years hence, twice his age will be
equal to five times that of his son. Find their
present ages.​

Answer 1

Answer:

i hope it's helpfull for you

Answer 2

Answer:

son's present age x = 14years.

Bunty's present age =(3×14) -4

Bunty's present age =38 years.

Step-by-step explanation:

let us consider

son's age=X

two years ago son's age =X-2

bunty's age at thar time=3(X-2)

present age of Bunty=3X-6+2

the present Age of bunty=3X-4

two years hence bunty's age =3X-4+2

two years hence bunty's age =3X-2

two years hence son's age =X+2

given

5 × (X+2) = 2×(3X-2)

5X + 10 =6X - 4

x=14

son's present age X = 14 years.

bunty's present age =(3 × 14) -4

bunty's present age = 38 years.

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