Question

4 upon 9 is equals to x-1 upon 2x-1
what's the value of x.​

Answer 1

Answer:

$\frac{4}{9} = \frac{x - 1}{2x - 1} \\ \\ = cross \: multiplication \\ \\ = 4(2x - 1) = 9(x - 1) \\ \\ = 8x - 4 = 9x - 9 \\ \\ = 9x - 8x = 9 - 4 \\ \\ = x = 5$

Answer 2

GIVEN :

$\sf \: \dfrac{4}{9} \:=\: \dfrac{x-1}{2x-1}$

To find : x

Solution :

1) Take 9 from LHS to RHS

$\sf \implies \: 4\:=\: \dfrac{(x-1)}{(2x-1)} \times 9$

2) Now from RHS take (2x-1) to LHS

$\sf \implies \: 4 \times (2x-1) \: = \: 9 \times (x-1 )\\ \\ \sf \implies 8x - 4 \: = \: 9x \: - \: 9$

3) Now take variable terms on one side and constant terms on one side.

• Take +8x from LHS to RHS
• Take (-9) from RHS to LHS

$\sf \implies \: 9 \: - \: 4 \: = \: 9x \: - \: 8x \\ \\ \sf \implies \: 5 = x \\ \sf \implies \bold{x = 5}$

ANSWER :

x = 5