Math, asked by yash6265, 11 months ago

4. Use Euclid's division lemma to show that the square of any positive integer is either of the form
3mor 3m - 1 for some integer m.​

Answers

Answered by Anonymous
2

Hi Beautiful Soul,

Use Euclid division lemma to show that

the square of any positive integer is

either of the form 3m or 3m+1 for some

integer m.

Let a be any positive integer and b=3.

=) a = 3q +r, r=0 or 1 or 2.

(By Euclid's lemma)

=) a = 3q or 3q +1 or 3q + 2 for positive

integer q.

1st case,

If a = 3q:

=) a = (3q)2

= 9

= 3(3q)

= 3m, where m= 3q

2nd case,

If a = 3q+1,

=) a? = (39+1)

= (3q) + 2(39)(1) + 12

= = 9q + 6q +1

= 3(3q2 + 2q) + 1

= 3m + 1, where m = 3q2 + 2q.

3rd case,

If a=3q+2:

=) a? = (39+2)2

= (39)2 + 2(39)(2)+22

= 9q? + 12q + 4

= = 9q? + 12q + 3+1

= 3(3q2 +4q + 1) + 1

= 3m + 1, where m = 3q+49 +1.

Therefore, the square of any positive integer is either of the form 3m or 3m+1.

All the very best for your Bright Future ❤

Answered by Anonymous
0

Answer:

It is the correct answer.

Step-by-step explanation:

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