Question

4) Using division state whether 2y – 5 is a factor of 4y4 – 10y3 – 10y2 + 30y – 15

Answer 1

p(y)=4y4-10y3-10y2+30y-15
p(5/2)=4(5/2)4-10(5/2)3+30(5/2)-15
         =4(625/16)—10(125/8)+150/2-15
         =625/4-625/4+150/2-15
         =(625-625+300-60)/4
         =240/4
         =60// 


Hope this was helpful ;)