4. Using Euclid's division algorithm, find the HCF of
(i) 405 and 2520 (ii) 504 and 1188 (iii) 960 and 1575.
Answers
Answered by
29
Answer:
(i) 405 and 2520
⇒ 2520 = 405 * 6 + 90
⇒ 405 = 90 * 4 + 45
⇒ 90 = 45 * 2 + 0
Hence, the HCF is 45.
_______________________
(ii) 504 and 1188
⇒ 1188 = 504 * 2 + 180
⇒ 504 = 180 * 2 + 144
⇒ 180 = 144 * 1 + 36
⇒ 144 = 36 * 4 + 0
Hence, the HCF is 36.
_______________________
(iii) 960 and 1575
⇒ 1575 = 960 * 1 + 615
⇒ 960 = 615 * 1 + 345
⇒ 615 = 345 * 1 + 270
⇒ 345 = 270 * 1 + 75
⇒ 270 = 75 * 3 + 45
⇒ 75 = 45 * 1 + 30
⇒ 45 = 30 * 1 + 15
⇒ 30 = 15 * 2 + 0
Hence, the HCF is 15.
_______________________
Answered by
1
Answer:
answer is in the attachment
(I) HCF is 45
(II) HCF is 36
(III) HCF is 15
Attachments:
Similar questions
English,
7 months ago
Science,
7 months ago
Social Sciences,
1 year ago
Biology,
1 year ago
Chemistry,
1 year ago