Question

4. Using Euclid's division algorithm, find the HF of
(i) 612 and 1314
​

Answer 1

Answer:

First we shall find the H.C.F of both the given numbers:

a=bq+r

i.e 1314=612x2+90

612=90 x 6+72

90=72 x 1+18

72= 18 x 4+0

Therefore:The HCF of both the given numbers is 18

Now to find LCM

612,1314 division

2(306,657)

3(102,219)

3(34,73)

34(1,73)

73(1,1)

By multiplying the numbers: 2 x 3 x 3 x 34 x 73=44676 which is the LCM

A helpful tip: HCF x LCM= Product of numbers

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