Question

(4) Using truth table prove that ~ ~ p q p q q p ~ . Solution : I II III IV V VI VII VIII IX p q ∼p ∼ q p ↔ q ∼( p ↔ q) p ∧ ~ q q∧ ~p (p∧∼q)∨(q∧∼p) T T T F F T F F From column (VI) and (IX) we conclude that ~ p q . . . . . . . . . . . . . . . . . . . . . . . . . .
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Answer 1

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