4. Verify that a ÷ (b +c) # (a ÷ b)+ (a ÷ c) for
(i) a = -10, b = 1 and ca = 1
(ii) a = 12, b = 1 and c = -2
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(i) a ÷ (b +c) # (a ÷ b)+ (a ÷ c)
let's take a÷(b+c) as LHS
And (a÷b)+(a÷c) as RHS
First we will do LHS
a÷(b+c)
= -10÷(1+1)
= -10÷2
= -5
RHS
(a÷b)+(a÷c)
=(-10÷1)+(-10÷1)
= -10+(-10)
= -10-10
= -20
Here, -5 # -20
Therefore, it's proof that a ÷ (b +c) # (a ÷ b)+ (a ÷ c)
(ii) a ÷ (b +c) # (a ÷ b)+ (a ÷ c)
LHS
a÷(b+c)
=12÷(1+(-2))
=12÷(1-2)
=12÷ -1
= -12
RHS
(a÷b)+(a÷c)
= (12÷1)+(12÷(-2))
= 12+ -6
= 12-6
= 6
Here, -12 # 6
Therefore, it's proof that a ÷ (b +c) # (a ÷ b)+ (a ÷ c)
HOPE IT CLEAR YOU
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