Question

4. Verify that points P(-2, 2), Q(2, 2) and R(2, 7) are vertices of a right angled
triangle
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Answer 1

Answer:PQ^2=(2--2)^2+(2-2)^2

=16

QR ^2=(2-2)^2+(7-2)^2

=25

PR^2=(2--2)^2+(7-2)^2

=16+25

=41

According to pythagorus theorem

PR^2=PQ^2+QR^2

41=16+25

41=41

That is it obey pythagorus theorem

therefore triangle PQR is right angled

Step-by-step explanation:

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Answer 2

1. Hope this will help you .