4. Verify that- (x÷y)-1 = x-1 ÷y-1x= z5/11, y=7/3.
Answers
Answer:
Answer:
It isn't correct/ both sides aren't equal
Step-by-step explanation:
NOTE: I don't know if any of the numbers were put in wrong because I double checked this and ran it through a calculator and it still wasn't equal
To verify that the equation is correct, we need to plug in the values of x and y. When we plug in the values for x and y, we get the new equation:
(\frac{-5}{11}/\frac{7}{3})-1=\frac{-5}{11} -1/\frac{7}{3} -1(
11
−5
/
3
7
)−1=
11
−5
−1/
3
7
−1
Next, we need to use PEMDAS ( parenthesis, exponents, multiplication, division, addition, subtraction ):
P ( parenthesis ):
\frac{-5}{11} /\frac{7}{3}
11
−5
/
3
7
or \frac{-5}{11} *\frac{3}{7} = \frac{-15}{77}
11
−5
∗
7
3
=
77
−15
Now we have the new equation:
\frac{-15}{77} -1=\frac{-5}{11} -1/\frac{7}{3} -1
77
−15
−1=
11
−5
−1/
3
7
−1
E ( exponents ): Nothing to do here
M ( multiplication ): Nothing to do here
D ( division ):
-1/\frac{7}{3}−1/
3
7
or -1*\frac{3}{7} =\frac{3}{7}−1∗
7
3
=
7
3
Now we have the new equation:
\frac{-15}{77} -1=\frac{-5}{11}- \frac{3}{7} -1
77
−15
−1=
11
−5
−
7
3
−1
A ( addition ): Nothing to do here
S ( subtraction ):
\frac{-15}{77} -1=\frac{-92}{77}
77
−15
−1=
77
−92
\frac{-5}{11}- \frac{3}{7} -1=\frac{-145}{77}
11
−5
−
7
3
−1=
77
−145
So, after all of this work, we know that this equation is NOT correct.
Hope this helped