Question

4. Vineet vacuum cleans his car every fourth day, washes it every fifth day, polishes it
every eighth day. If he cleaned the car with all 3 activities on 1st June, when will he be
doing all the three activities on the same day again?
a. 10th July
b. 11th July
C. 18th July
d. 5th June​

Answer 1

Answer:11 july

Step-by-step explanation:lcm of 4,5,8=40

1st june + 40 days = 11 july

Answer 2

Answer:

Vineet will do all the three activities on the same day again on a. 10th  July.

Step-by-step explanation:

It is given that Vineet cleans his car every fourth day, washes it every fifth day, and polishes it every eighth day.

He did all the three activities on 1st June.

We have to find when he will do all the three activities on the same day again.

• The car is cleaned after 4 days.
• The car is washed after 5 days.
• The car is polished after 8 days.

So, to find the day when all the activities are done together, we need to find the least common multiple of 4, 5, and 8.

The LCM of 4, 5, and 8 is given as follows:

LCM = 4 | 4, 5, 8

LCM = 2 | 1, 5, 2

LCM = 5 | 1, 5, 1

LCM =    | 1, 1, 1

LCM = 4×2×5

LCM = 40

Hence, the three activities will be performed on the same day again after 40 days.

1st June to 30th June = 30 days

1st July to 10th July = 10 days

1st June to 10th July = 40 days

Therefore, on 10th July, Vineet will be doing all the three activities again.

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