Question

4. Water is flowing through a horizontal pipe of
non-uniform cross-section. The speed of water is
30 cm s at a place where pressure is 10 cm Cof
water). Calculate the speed of water at the other place
where the pressure is half of that at the first place.
​

Answer 1

We can solve this question by using Bernoulli's theorem.

Which is,

Where,

P = pressure

d = density of the liquid

V = velocity

h = height

g = acceleration due to gravity

but this question states that there is a horizontal pipe. so height should be zero.

now we can change above equation as below,

but we know that, pressure (P) = hdg

----- (1)

substituting values for above equation,

h1g + (1/2)v1² = h2g + (1/2)v2²

10×10 + (1/2)×(30)² = 5×10 + (1/2)×(V2)²

100 + 450 = 50 + (v2²/2)

500 = v2²/2

1000 =v2²

31.62 cm/s =v2

hope it helps dear... ✌